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- From: Kin Yip <kinyip AT bnl.gov>
- To: "sphenix-magnet-l AT lists.bnl.gov" <sphenix-magnet-l AT lists.bnl.gov>
- Subject: [Sphenix-magnet-l] ohm to temperature (K)
- Date: Tue, 2 Feb 2016 19:25:24 -0500
Hi Piyush, Have you figured out how to get the temperature from ohm or voltage ? The ohm or voltage should be the same thing if you have "constant current" (especially high-precision). Paul Giannotti told me to look at 2.4. So, in //bnl.gov/c-adnas/babar/Volume 2 DESCRIPTION OF COMPONENTS/2.4 GAUGES AND INSTRUMENT CONNECTIONS, there is the "2.4 Gauges & Instrument Connections.pdf" There are 369 pages with many nos. and curves. I'm not sure whether the latter stuff are relevant (as they refer to various instrument). But on p.7-11, they have 3 resistance and 3 temperatures (temperatures are 4.2 K to 77.4 K to 295 K). I took a snapshot6.png. Since there are 3 points, I can do a quadratic fit which almost looks linear (but not quite). I show you the fit on TT01.gif for TT01. So, temperature (K) = a + b*ohm + c*ohm^2 and the following are the coefficients from my fit : TT01: -1017.35 , 5.05676 , -0.00187896 TT02: -916.28 , 4.22621 , -0.000191854 TT03: -868.795 , 3.88358 , 0.000384459 I've assumed the resistances are in ohm. I hope this helps. Kin |
Attachment:
snapshot6.png
Description: PNG image
Attachment:
TT01.gif
Description: GIF image
- [Sphenix-magnet-l] ohm to temperature (K), Kin Yip, 02/02/2016
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