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[Sphenix-magnet-l] power consumption estimation in water-cooled-bus ... and delta-T
- From: "Yip, Kin" <kinyip AT bnl.gov>
- To: "Streckenbach, Brian" <bstreckenbach AT bnl.gov>, "sphenix-magnet-l AT lists.bnl.gov" <sphenix-magnet-l AT lists.bnl.gov>
- Subject: [Sphenix-magnet-l] power consumption estimation in water-cooled-bus ... and delta-T
- Date: Wed, 30 Sep 2020 18:18:45 +0000
Hi,
This is a follow-up to the previous email and I change the subject to represent the subject a bit better.
(1)
While chatting with Carl, he made me remember that the nature of using 2 WCB’s (sharing 4600 A) per sign (+/-) made the above estimation a factor of 2 wrong.
So, if I use the above assumption of 100 ft, each WCB is 0.00034 Ohm but each has only 4600/2 ~ 2300 A
Nevertheless, 100 ft is probably an underestimate of the total WCB length; but it should be <200 ft (last time Brian estimated when we bought cables). Brian is going to measure it again. If we use 200 ft, resistance is 6.8E-4 Ohm (for each WCB), total power = 7.194 kW again 😊
{ I guess Dave probably just used the 200 ft. }
Roberto Than talked to me about the temperature gradient in the WCB (between the inner diameter of the bus and the water flow). He made an estimation of the delta-T which I enclose below.
***************************************************** Roberto ****************************************************** Water flow Water temperature and Heat transfer gradient between water and water cooled bus sets the final operating temperature of the power bus. The final operating temperature sets the electrical resistance of bus, and thus the final Joule losses power dissipation. Not too bad as expected.
**************************************************************************************************************************************************
Kin
From: sPHENIX-magnet-l <sphenix-magnet-l-bounces AT lists.bnl.gov>
On Behalf Of Yip, Kin
Hi, Bob Lambiase gave me some ideas ... Modifying those ideas a bit, I plug in some nos. and apply them to various Ohm's laws:
(1) Water-cooled-bus ... Say, let's call the resistance 3.4 µΩ / ft. (near the higher end of Dave's range). R(100 ft) => 0.00034 Ohm ( for each sign) Power = I^2 * R where I ~ 4600 A ~ 7.194 kW ... close to Dave's 7.2 kW (each). { We probably shouldn't count the distance in the air between 1008B and 1008 ...as mother nature takes of those ?!}
(2) Say, our total resistance is like BaBar's ~1.25E-3 Ohm. Static Voltage across the dump resistor: V = 4600 A * 1.25E-3 Ohm ~ 5.75 V [ When it quenches, it's much larger .. but quench only last 38 sec < a minute ...]
Power in dump resistor (0.068 Ohm) ~ V^2/0.068 ~ 486 W close to Dave's 0.5 kW.
(3) Power Supply, this one we have to check with Pablo. There are 2 SCR's ? If each one is 1 V, total power (for two) = 2*1V*4600A ~ 9.2 kW, just a bit bigger than Dave's 8 kW.
I wrote this Kin On 9/29/20 3:57 PM, Streckenbach, Brian wrote:
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[Sphenix-magnet-l] power consumption estimation in water-cooled-bus ... and delta-T,
Yip, Kin, 09/30/2020
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Re: [Sphenix-magnet-l] power consumption estimation in water-cooled-bus ... and delta-T,
Streckenbach, Brian, 09/30/2020
- Re: [Sphenix-magnet-l] power consumption estimation in water-cooled-bus ... and delta-T, Than, Yatming (Roberto), 09/30/2020
- Re: [Sphenix-magnet-l] power consumption estimation in water-cooled-bus ... and delta-T, Yip, Kin, 09/30/2020
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Re: [Sphenix-magnet-l] power consumption estimation in water-cooled-bus ... and delta-T,
Streckenbach, Brian, 09/30/2020
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